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How can the momentum operator for a particle in one dimension be obtained from the Hamiltonian?

by EITCA Academy / Sunday, 06 August 2023 / Published in Quantum Information, EITC/QI/QIF Quantum Information Fundamentals, Instroduction to implementing qubits, Schrodinger's equation for a 1D free particle, Examination review

To understand how the momentum operator for a particle in one dimension can be obtained from the Hamiltonian, we need to consider the principles of quantum mechanics and the mathematical framework it provides. In quantum mechanics, the momentum operator is a fundamental quantity that describes the motion of a particle, while the Hamiltonian represents the total energy of the system. The relationship between these two operators can be derived using the principles of quantum mechanics.

Let's consider a particle in one dimension, which can be described by the wave function Ψ(x, t), where x represents the position of the particle and t represents time. The time evolution of the wave function is governed by the Schrödinger equation:

iħ ∂Ψ(x, t) / ∂t = H Ψ(x, t),

where i is the imaginary unit, ħ is the reduced Planck's constant, H is the Hamiltonian operator, and ∂/∂t denotes the partial derivative with respect to time.

For a free particle in one dimension, the Hamiltonian operator is given by:

H = (p^2 / 2m) + V(x),

where p is the momentum operator, m is the mass of the particle, and V(x) is the potential energy. In the case of a free particle, the potential energy is zero.

To obtain the momentum operator, we need to express the Hamiltonian in terms of the momentum operator p. Let's start by expanding the square of the momentum operator:

p^2 = (-ħ^2 / 2m) (∂^2 / ∂x^2).

Substituting this into the expression for the Hamiltonian, we have:

H = (-ħ^2 / 2m) (∂^2 / ∂x^2) + V(x).

Now, we can rearrange the terms to isolate the momentum operator:

H – V(x) = (-ħ^2 / 2m) (∂^2 / ∂x^2).

Multiplying both sides of the equation by -2m/ħ^2, we obtain:

(-2m/ħ^2)(H – V(x)) = (∂^2 / ∂x^2).

Finally, we can express the momentum operator as:

p = iħ (∂ / ∂x),

where we have used the fact that (∂^2 / ∂x^2) = -k^2, with k being the wave number.

Therefore, the momentum operator for a particle in one dimension can be obtained from the Hamiltonian as:

p = iħ (∂ / ∂x).

This result shows that the momentum operator is proportional to the derivative of the wave function with respect to position, multiplied by the imaginary unit i and the reduced Planck's constant ħ.

The momentum operator for a particle in one dimension can be obtained from the Hamiltonian by expressing the Hamiltonian in terms of the momentum operator and rearranging the terms to isolate the momentum operator. This derivation is based on the principles of quantum mechanics and the Schrödinger equation, providing a mathematical framework for understanding the behavior of quantum systems.

Other recent questions and answers regarding EITC/QI/QIF Quantum Information Fundamentals:

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View more questions and answers in EITC/QI/QIF Quantum Information Fundamentals

More questions and answers:

  • Field: Quantum Information
  • Programme: EITC/QI/QIF Quantum Information Fundamentals (go to the certification programme)
  • Lesson: Instroduction to implementing qubits (go to related lesson)
  • Topic: Schrodinger's equation for a 1D free particle (go to related topic)
  • Examination review
Tagged under: Hamiltonian, Momentum Operator, Quantum Information, Quantum Mechanics, Schrödinger Equation, Wave Function
Home » EITC/QI/QIF Quantum Information Fundamentals / Examination review / Instroduction to implementing qubits / Quantum Information / Schrodinger's equation for a 1D free particle » How can the momentum operator for a particle in one dimension be obtained from the Hamiltonian?

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