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Under what conditions does the entropy of a random variable vanish, and what does this imply about the variable?

by EITCA Academy / Saturday, 26 August 2023 / Published in Cybersecurity, EITC/IS/QCF Quantum Cryptography Fundamentals, Entropy, Classical entropy, Examination review

The entropy of a random variable refers to the amount of uncertainty or randomness associated with the variable. In the field of cybersecurity, particularly in quantum cryptography, understanding the conditions under which the entropy of a random variable vanishes is important. This knowledge helps in assessing the security and reliability of cryptographic systems.

The entropy of a random variable X is defined as the average amount of information, measured in bits, needed to describe the outcomes of X. It quantifies the uncertainty associated with the variable, with higher entropy indicating greater randomness or unpredictability. Conversely, when the entropy is low or vanishes, it implies that the variable has become deterministic, meaning that its outcomes can be predicted with certainty.

In the context of classical entropy, the conditions under which the entropy of a random variable vanishes depend on the probability distribution of the variable. For a discrete random variable X with a probability mass function P(X), the entropy H(X) is given by the formula:

H(X) = – Σ P(x) log2 P(x)

where the summation is taken over all possible values x that X can take. When the entropy H(X) equals zero, it means that there is no uncertainty or randomness associated with X. This occurs when the probability mass function P(X) assigns a probability of 1 to a single outcome and a probability of 0 to all other outcomes. In other words, the variable becomes completely deterministic.

To illustrate this concept, consider a fair coin toss. The random variable X represents the outcome of the toss, with two possible values: heads (H) or tails (T). In this case, the probability mass function is P(H) = 0.5 and P(T) = 0.5. Calculating the entropy using the formula above:

H(X) = – (0.5 * log2(0.5) + 0.5 * log2(0.5))
= – (0.5 * (-1) + 0.5 * (-1))
= – (-0.5 – 0.5)
= – (-1)
= 1 bit

The entropy of the coin toss is 1 bit, indicating that there is uncertainty or randomness associated with the outcome. However, if the coin is biased and always lands on heads, the probability mass function becomes P(H) = 1 and P(T) = 0. The entropy calculation becomes:

H(X) = – (1 * log2(1) + 0 * log2(0))
= – (1 * 0 + 0 * undefined)
= – (0 + undefined)
= undefined

In this case, the entropy is undefined because the logarithm of zero is undefined. However, it implies that the variable X has become deterministic, as it always yields heads.

The entropy of a random variable in the context of classical entropy vanishes when the probability distribution assigns a probability of 1 to a single outcome and a probability of 0 to all other outcomes. This indicates that the variable becomes deterministic and loses its randomness or unpredictability.

Other recent questions and answers regarding Classical entropy:

  • How does understanding entropy contribute to the design and evaluation of robust cryptographic algorithms in the field of cybersecurity?
  • What is the maximum value of entropy, and when is it achieved?
  • What are the mathematical properties of entropy, and why is it non-negative?
  • How does the entropy of a random variable change when the probability is evenly distributed between the outcomes compared to when it is biased towards one outcome?
  • How does binary entropy differ from classical entropy, and how is it calculated for a binary random variable with two outcomes?
  • What is the relationship between the expected length of code words and the entropy of a random variable in variable length coding?
  • Explain how the concept of classical entropy is used in variable length coding schemes for efficient information encoding.
  • What are the properties of classical entropy and how does it relate to the probability of outcomes?
  • How does classical entropy measure the uncertainty or randomness in a given system?

More questions and answers:

  • Field: Cybersecurity
  • Programme: EITC/IS/QCF Quantum Cryptography Fundamentals (go to the certification programme)
  • Lesson: Entropy (go to related lesson)
  • Topic: Classical entropy (go to related topic)
  • Examination review
Tagged under: Cybersecurity, Deterministic, Probability Distribution, Quantum Cryptography, Random Variable, Uncertainty
Home » Classical entropy / Cybersecurity / EITC/IS/QCF Quantum Cryptography Fundamentals / Entropy / Examination review » Under what conditions does the entropy of a random variable vanish, and what does this imply about the variable?

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